To solve the inequality X + 8 > 10, we need to isolate X.
First, we subtract 8 from both sides of the inequality:
X + 8 - 8 > 10 - 8
This simplifies to:
X > 2
So, the solution to the inequality is X > 2.
X +8>10
9 answers
X - 1/3 _< 1/2
To solve the inequality X - 1/3 ≤ 1/2, we need to isolate X.
First, we add 1/3 to both sides of the inequality:
X - 1/3 + 1/3 ≤ 1/2 + 1/3
This simplifies to:
X ≤ 5/6
So, the solution to the inequality is X ≤ 5/6.
First, we add 1/3 to both sides of the inequality:
X - 1/3 + 1/3 ≤ 1/2 + 1/3
This simplifies to:
X ≤ 5/6
So, the solution to the inequality is X ≤ 5/6.
X+3 _< 7
Show on graph what points would it be on
Show on graph what points would it be on
To graph the inequality X + 3 < 7, we can start by drawing a number line.
First, mark the number 7 on the number line. Then, mark the point 3 units to the left of 7, which is the number 4. This represents the solution boundary for the inequality.
Next, because the inequality is less than (<), we use an open circle at the point 4 on the number line to indicate that 4 is not included in the solution set.
Lastly, draw an arrow pointing to the left from the open circle to indicate that any value less than 4 is part of the solution set.
The graph of the inequality X + 3 < 7 would look like this:
-∞ ------o---> 4 ------o------ 7 +∞
First, mark the number 7 on the number line. Then, mark the point 3 units to the left of 7, which is the number 4. This represents the solution boundary for the inequality.
Next, because the inequality is less than (<), we use an open circle at the point 4 on the number line to indicate that 4 is not included in the solution set.
Lastly, draw an arrow pointing to the left from the open circle to indicate that any value less than 4 is part of the solution set.
The graph of the inequality X + 3 < 7 would look like this:
-∞ ------o---> 4 ------o------ 7 +∞
No my starting point is 4 or 10
Or 4 or 10
Or 4 or 10
I apologize for the confusion earlier. If your starting point is either 4 or 10, we need to consider two separate cases.
Case 1: Starting point is 4
To graph the inequality X + 3 < 7 with a starting point of 4, we follow the same steps as before.
First, mark the number 7 on the number line. Then, mark the point 3 units to the left of 7, which is the number 4. This represents the solution boundary for the inequality.
Since the inequality is strict (<), we use an open circle at the point 4 on the number line to indicate that 4 is not included in the solution set.
Lastly, draw an arrow pointing to the right from the open circle to indicate that any value greater than 4 is part of the solution set.
The graph for the inequality X + 3 < 7 with a starting point of 4 would look like this:
-∞ ------o------ 4 ------o---> 7 +∞
Case 2: Starting point is 10
To graph the inequality X + 3 < 7 with a starting point of 10, we once again need to follow the same steps.
First, mark the number 7 on the number line. Then, mark the point 3 units to the left of 7, which is the number 4. This represents the solution boundary for the inequality.
Since the inequality is strict (<), we use an open circle at the point 4 on the number line to indicate that 4 is not included in the solution set.
Lastly, draw an arrow pointing to the left from the open circle to indicate that any value less than 4 is part of the solution set.
The graph for the inequality X + 3 < 7 with a starting point of 10 would still look like this:
-∞ ------o---> 4 ------o------ 7 +∞
Please let me know if you have any further questions or if there is anything else I can assist you with.
Case 1: Starting point is 4
To graph the inequality X + 3 < 7 with a starting point of 4, we follow the same steps as before.
First, mark the number 7 on the number line. Then, mark the point 3 units to the left of 7, which is the number 4. This represents the solution boundary for the inequality.
Since the inequality is strict (<), we use an open circle at the point 4 on the number line to indicate that 4 is not included in the solution set.
Lastly, draw an arrow pointing to the right from the open circle to indicate that any value greater than 4 is part of the solution set.
The graph for the inequality X + 3 < 7 with a starting point of 4 would look like this:
-∞ ------o------ 4 ------o---> 7 +∞
Case 2: Starting point is 10
To graph the inequality X + 3 < 7 with a starting point of 10, we once again need to follow the same steps.
First, mark the number 7 on the number line. Then, mark the point 3 units to the left of 7, which is the number 4. This represents the solution boundary for the inequality.
Since the inequality is strict (<), we use an open circle at the point 4 on the number line to indicate that 4 is not included in the solution set.
Lastly, draw an arrow pointing to the left from the open circle to indicate that any value less than 4 is part of the solution set.
The graph for the inequality X + 3 < 7 with a starting point of 10 would still look like this:
-∞ ------o---> 4 ------o------ 7 +∞
Please let me know if you have any further questions or if there is anything else I can assist you with.
X + 3 <_ 7
To graph the inequality X + 3 ≤ 7, we can follow these steps:
1. Draw a number line.
2. Mark the number 7 on the number line.
3. Since the inequality is inclusive (≤), we use a closed circle at the point 7 to indicate that 7 is included in the solution set.
4. Next, draw an arrow pointing to the left from the closed circle to indicate that any value less than or equal to 7 is also part of the solution set.
The graph for the inequality X + 3 ≤ 7 would look like this:
-∞ ------o------> 7 +∞
1. Draw a number line.
2. Mark the number 7 on the number line.
3. Since the inequality is inclusive (≤), we use a closed circle at the point 7 to indicate that 7 is included in the solution set.
4. Next, draw an arrow pointing to the left from the closed circle to indicate that any value less than or equal to 7 is also part of the solution set.
The graph for the inequality X + 3 ≤ 7 would look like this:
-∞ ------o------> 7 +∞