Asked by gary
x=6y/5-8y-3y+9y,what is the value of y in terms of x ?
Answers
Answered by
Reiny
x=6y/5-8y-3y+9y
multiply each term by 5 to get rid of fractions
5x = 6y - 40y - 15y + 45y
5x = -4x
x = -5x/4
multiply each term by 5 to get rid of fractions
5x = 6y - 40y - 15y + 45y
5x = -4x
x = -5x/4
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