Substitute the value of x into the second equation:
2(6y-3) + 7y = 13
12y - 6 + 7y = 13
19y - 6 = 13
19y = 19
y = 1
Now substitute the value of y back into the first equation to find the value of x:
x = 6(1) - 3
x = 6 - 3
x = 3
Therefore, the solution to the system of equations is x = 3 and y = 1.
x=6y−3
2x+7y=13
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