(x-1) is the altitude I assume?
if so
(x-1)(1/2)(x+6+3x-4) = 119
(x-1)(4x+2) = 119*2
(x-1)(2x+1) = 119
2x^2 - x - 120 = 0
(x-8)(2x+15)
x = 8
X+6
_________
| \
| \
|x-1 \
| \
|____________\
3x-4
The area of the trapezium is 119cm.
What is the value of x?
Thank you.
1 answer
1 answer