Kelsey, chi -- or whatever your name is. I already responded to this question.
http://www.jiskha.com/display.cgi?id=1284076266
(x+5)(x+2)
(x-2)(x-2)
(x+5)(x-12)
(3c-4d)(2c+5d)
(5x-3)(3x-8)
1 answer
(x-2)(x-2)
(x+5)(x-12)
(3c-4d)(2c+5d)
(5x-3)(3x-8)
1 answer