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x^4/3-7x^2/3+12=0 implify into quadratic equation

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First of all multiply by 3

x^4 - 7x^2 + 36 = 0
then
(x^2)^2 - 7(x^2) +36 = 0

um . . . how can it be in the form of ax^2 + bx + c = 0?

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