∫(x^3-x^2) dx/x^2 =∫(x^3/x^2-x^2/x^2)dx
= ∫(x^3/x^2-x^2/x^2)dx
= ∫(x-1)dx
= (x^2/2) - x + c
which is the fourth option and is also what you got
∫(x^3-x^2)/x^2
I got (x^2)/(2)-x + C but that's not one of the answers
Options
x - 1 + C
(x^2/2)-(x^3/3) + C
(x^4-x^3)/4x^2 + C
(x^2/2) -x + C
3 answers
Oh shoot I misread my answer. Thanks
You are welcome.