Question

x^3 + 8x^2 = 20x

How do I find the root of ^ that equation?

2x^2-10x+12 = 0

^ I found that one by...

2(x-3)(x-2)
x-3 = 0
x = 3
x-2 = 0
x =2

^ Is that the correct way to solve for that one?

Answer 1

Your solution to the second equation is correct, and the procedure also.

For the first equation, think of it as:
x^3 + 8x^2 = 20x
x^3 + 8x^2 - 20x = 0
x(x^2 + 8x - 20) = 0
then x=0 is a solution, and you can get two more solutions from the part in parentheses in a similar way to the second equation.

Answer 2

Thanks so much MathMate =)

Answer 3

You're welcome, and keep up the good work!