http://www.purplemath.com/modules/remaindr.htm
You need to do some synthetic division.
x^3+3x^2-10x-24/ (x+4)
The remainder for this is zero. Correct?
5 answers
I did and I arrived at 0. Were my calculations correct?
Correct!
You can also use the fact that
f(x)/(x-k) has a remainder of f(k).
In this case,
f(x)=x^3+3x^2-10x-24
k=-4
so evaluate
Remainder of f(x)/(x-k)
=Remainder of (x^3+3x^2-10x-24)/(x+4)
=f(-4)
=(-4)^3+3(-4)^2-10(-4)-24
=-64+48+40-24
=0
You can also use the fact that
f(x)/(x-k) has a remainder of f(k).
In this case,
f(x)=x^3+3x^2-10x-24
k=-4
so evaluate
Remainder of f(x)/(x-k)
=Remainder of (x^3+3x^2-10x-24)/(x+4)
=f(-4)
=(-4)^3+3(-4)^2-10(-4)-24
=-64+48+40-24
=0
Thanks!
You're welcome!