Steve did this for you earlier.
What did you not like about his reply?
http://www.jiskha.com/display.cgi?id=1486532823
You could graph:
y = x^3 and y = 3^x and see where they cross
x^3=3^x
plz help me what is the solution yes i know x=3 but how?
3 answers
how about newton literative method?
Payoto
Payoto
you mean Newton's "iterative" method
sure, why not?
x^3 = 3^x
let y = x^3 - 3^x
dy/dx = 3x^2 - ln3(3^x)
newx= x - (x^3 - 3^x)/(3x^2 - ln3 (3^x) )
start with x = 2.9
newx = appr 3.0471... using that
newx = appr 3.0081... using that
newx = appr 3.00006996 , not bad
sure, why not?
x^3 = 3^x
let y = x^3 - 3^x
dy/dx = 3x^2 - ln3(3^x)
newx= x - (x^3 - 3^x)/(3x^2 - ln3 (3^x) )
start with x = 2.9
newx = appr 3.0471... using that
newx = appr 3.0081... using that
newx = appr 3.00006996 , not bad
9 answers