-2x^(2) / (1/3)^(-x)
when x = 3 I get
-2(9)/(1/3)^-3
= -18(1/3)^+3
= -18(1/27)
= -2/3
x = 3
-2x^(2) / (1/3)^(-x)
how to solve?
would I multiply 3(-2) than square?
Also, when I move (1/3)^(-3) to the numerator would it become (3)^3
1 answer