To determine which ordered pairs are solutions to the given system of inequalities, we need to plug each pair into both inequalities:
- \( x + 2y \geq 10 \)
- \( 3x - 4y > 12 \)
We will check each possible ordered pair:
-
(4, -4):
- For the first inequality: \( 4 + 2(-4) = 4 - 8 = -4 \) (not ≥ 10)
- For the second inequality: \( 3(4) - 4(-4) = 12 + 16 = 28 \) (> 12)
- Not a solution.
-
(10, 2):
- For the first inequality: \( 10 + 2(2) = 10 + 4 = 14 \) (≥ 10)
- For the second inequality: \( 3(10) - 4(2) = 30 - 8 = 22 \) (> 12)
- Solution.
-
(14, -1):
- For the first inequality: \( 14 + 2(-1) = 14 - 2 = 12 \) (not ≥ 10)
- For the second inequality: \( 3(14) - 4(-1) = 42 + 4 = 46 \) (> 12)
- Not a solution.
-
(-4, 2):
- For the first inequality: \( -4 + 2(2) = -4 + 4 = 0 \) (not ≥ 10)
- For the second inequality: \( 3(-4) - 4(2) = -12 - 8 = -20 \) (not > 12)
- Not a solution.
-
(2, 6):
- For the first inequality: \( 2 + 2(6) = 2 + 12 = 14 \) (≥ 10)
- For the second inequality: \( 3(2) - 4(6) = 6 - 24 = -18 \) (not > 12)
- Not a solution.
-
(8, 1):
- For the first inequality: \( 8 + 2(1) = 8 + 2 = 10 \) (≥ 10)
- For the second inequality: \( 3(8) - 4(1) = 24 - 4 = 20 \) (> 12)
- Solution.
Summary of solutions:
- (10, 2)
- (8, 1)
Therefore, the solutions to the system of inequalities are (10, 2) and (8, 1).