(x/2)^2 + (y/3)^2 = 0
Since x and y have opposite signs, you are in the second or fourth quadrant of an ellipse.
The 0 < t < pi requirement restricts you to the second quadrant.
x=2sint
y=-3cost
0<[smaller and equal to] t <[larger and equal to] pie
find a cartesian equation for the parametrized curve what portion of the graph of the cartesian equation is traced by the parametrized curve?
1 answer