involves a bit of mathematical "trickery"
we know
(x-y)^2 = x^2 - 2xy + y^2
= x^2 + y^2 - 2xy
= 86 + 32 = 118
real easy, right ?
x^2+y^2=86 and xy=(-16), Find the value of
(x-y)^2
Please help i am a bit tense today so i can't figure it out.
1 answer
1 answer