1. x = 9/12 or x = -9/12
2. x = 3/4 or x = -3/4
3. x = 9/12 only
4. x = -3/4 only
x^2 = 81/144 Which statement(s) true when solving the equation for x ?
3 answers
If you want the diagonal, d, to be at least 41.5 inches, what would be a possible length, width, and height for a box?
To find the minimum values for the length, width, and height of the box to have a diagonal length of at least 41.5 inches, we can use the formula for the diagonal of a rectangular box:
d = √(length^2 + width^2 + height^2)
Given that d ≥ 41.5, and we want to minimize the values of length, width, and height, we can set height equal to length and width:
41.5 ≤ √(length^2 + length^2 + length^2)
41.5 ≤ √(3*length^2)
(41.5)^2 ≤ 3*length^2
(41.5)^2 / 3 ≤ length^2
697.22 / 3 ≤ length^2
232.41 ≤ length^2
√232.41 ≤ length
15.24 ≤ length
So, a possible length, width, and height for the box to have a diagonal of at least 41.5 inches would be approximately 15.24 inches for each side.
d = √(length^2 + width^2 + height^2)
Given that d ≥ 41.5, and we want to minimize the values of length, width, and height, we can set height equal to length and width:
41.5 ≤ √(length^2 + length^2 + length^2)
41.5 ≤ √(3*length^2)
(41.5)^2 ≤ 3*length^2
(41.5)^2 / 3 ≤ length^2
697.22 / 3 ≤ length^2
232.41 ≤ length^2
√232.41 ≤ length
15.24 ≤ length
So, a possible length, width, and height for the box to have a diagonal of at least 41.5 inches would be approximately 15.24 inches for each side.
7 answers