x/2+6<3 on a number line

Answer 1

To graph x/2 + 6 < 3 on a number line, we first need to isolate x by subtracting 6 from both sides of the inequality:

x/2 + 6 - 6 < 3 - 6

x/2 < -3

Next, we multiply both sides of the inequality by 2 to get rid of the fraction:

2*(x/2) < -3*2

x < -6

Now, we graph x < -6 on the number line by plotting an open circle at -6 and shading to the left of it to represent all the values of x that are less than -6.

Number line: (-∞, -6)

Therefore, the graph of x/2 + 6 < 3 on a number line is all values of x to the left of -6.

Answer 2

x/2+3<6 on a number line

Answer 3

To graph x/2 + 3 < 6 on a number line, we first need to isolate x by subtracting 3 from both sides of the inequality:

x/2 + 3 - 3 < 6 - 3

x/2 < 3

Next, we multiply both sides of the inequality by 2 to get rid of the fraction:

2*(x/2) < 3*2

x < 6

Now, we graph x < 6 on the number line by plotting an open circle at 6 and shading to the left of it to represent all the values of x that are less than 6.

Number line: (-∞, 6)

Therefore, the graph of x/2 + 3 < 6 on a number line is all values of x to the left of 6.