X + 2/3 < 9, Solve inequality..write as mixed number

Answer 1

To solve the inequality \( X + \frac{2}{3} < 9 \), follow these steps:

1. Subtract \( \frac{2}{3} \) from both sides:

\[ X < 9 - \frac{2}{3} \]

2. To perform the subtraction, convert 9 to a fraction with a denominator of 3:

\[ 9 = \frac{27}{3} \]

3. Now, subtract the fractions:

\[ X < \frac{27}{3} - \frac{2}{3} = \frac{27 - 2}{3} = \frac{25}{3} \]

4. To convert \( \frac{25}{3} \) into a mixed number, divide 25 by 3:

• 25 divided by 3 is 8 with a remainder of 1, so:

\[ \frac{25}{3} = 8 \frac{1}{3} \]

Thus, the solution to the inequality is:

\[ X < 8 \frac{1}{3} \]