-x+1y+5=0

Question

I need to do PEMDAS but backwards for this equation and I am a bit confused. I need to follow PEMDAS but backwards please help.

Answer 1

To solve the equation \(-x + 1y + 5 = 0\) using steps that can be thought of as "PEMDAS backwards," we will isolate the variable \(y\). Here’s the process step by step:

1. Start with the equation: \[ -x + 1y + 5 = 0 \]

2. Subtract 5 from both sides (this is akin to "undoing" the addition in PEMDAS): \[ -x + 1y = -5 \]

3. Add \(x\) to both sides (undoing the subtraction): \[ 1y = x - 5 \]

4. Since \(1y\) is just \(y\), we can write: \[ y = x - 5 \]

There you have the equation solved for \(y\). So the final solution in terms of \(y\) is: \[ y = x - 5 \]

This completes the process, reversing the order of operations to isolate \(y\).

Answer 2

Awesome thank you for writing it out for me so y =x-5 but I have to also solve it that x=5 how could I solve that?

Answer 3

To solve for \(y\) when \(x = 5\) using the equation \(y = x - 5\), you simply substitute \(5\) in place of \(x\):

1. Start with the equation: \[ y = x - 5 \]

2. Substitute \(x = 5\): \[ y = 5 - 5 \]

3. Calculate the right side: \[ y = 0 \]

So when \(x = 5\), the corresponding value of \(y\) is: \[ y = 0 \]

The solution is \((x, y) = (5, 0)\).

Answer 4

My answer was supposed to be y=4x-5, y= 15 :(
Aw, did I do something wrong?

Answer 5

It looks like there might have been a misunderstanding about the original equation. Let's clarify.

The original equation was \(-x + 1y + 5 = 0\), which we simplified to \(y = x - 5\). However, if your intent was to get a different form of the equation (like \(y = 4x - 5\)), it suggests that either the original equation was different, or there might be a misunderstanding in how the equation was worked out.

To check if \(y = 4x - 5\) should be a correct form of your line, let’s find out if it’s consistent with any specific points.

If the equation is indeed supposed to be \(y = 4x - 5\):

1. You can express \(y = 4x - 5\).
2. Substituting \(x = 5\) into this new equation: \[ y = 4(5) - 5 \] \[ y = 20 - 5 \] \[ y = 15 \]

So, if \(y = 4x - 5\) is the equation you need, and you substitute \(x = 5\), you get \(y = 15\), which aligns with the value you expected.

Summary:

• If your goal was \(y = 4x - 5\) instead of the original line we discussed, then that changes your calculations. Please confirm the original equation you started with, and we can resolve any issues or clarify as needed!

Answer 6

Well my original equation was -x+1/4y + 5/4 =0
But I cleared out the fractions and yeah I think when I cleared out the fractions I made it wrong. I’m so sorry about that

Answer 7

No problem at all! Let's work through the original equation you provided, which is \(-x + \frac{1}{4}y + \frac{5}{4} = 0\). We will clear the fractions properly and solve for \(y\).

Step 1: Clear the Fractions

To eliminate the fractions, you can multiply the entire equation by \(4\) (the denominator of the fractions):

\[ 4 \left(-x + \frac{1}{4}y + \frac{5}{4}\right) = 0 \]

This simplifies to:

\[ -4x + y + 5 = 0 \]

Step 2: Rearranging the Equation

Now, let's rearrange this equation to solve for \(y\):

\[ y = 4x - 5 \]

Summary

Now we have the equation:

\[ y = 4x - 5 \]

Step 3: Substitute \(x = 5\)

Now, if you need to find \(y\) when \(x = 5\), substitute \(5\) into the equation:

\[ y = 4(5) - 5 \]

Calculating this gives:

\[ y = 20 - 5 = 15 \]

So, you are correct! The values you were expecting (i.e., \(y = 4x - 5\) and when \(x = 5\), \(y = 15\)) are indeed valid once you start with the original equation.

If you have any other questions or need further assistance, feel free to ask!

Answer 8

I am in an advanced algebra 2 college level class is this solution ok to present?

Answer 9

Yes, the solution we outlined is perfectly acceptable for an advanced Algebra 2 college-level class. It demonstrates the following key aspects:

1. Understanding the Problem: You clearly stated your original equation and recognized the need to simplify it by eliminating fractions, which shows your analytical ability.

2. Manipulation of the Equation: You correctly multiplied through by \(4\) to eliminate the fractions, leading you to a linear equation in standard form.

3. Solving for y: You accurately rearranged the equation to isolate \(y\), obtaining the slope-intercept form \(y = 4x - 5\). This is a crucial skill in algebra, as it helps in graphing the equation and understanding its properties.

4. Substituting Values: By substituting \(x = 5\), you calculated \(y = 15\), demonstrating the ability to apply the equation to specific values, which is often required in problems involving lines.

Presentation Tips

When you present the solution, it might be helpful to:

• Explain each step clearly: Make sure to verbalize why you multiplied by \(4\), your reasoning for rearranging the equation, and the significance of obtaining the slope-intercept form.

• Show the final form of the equation: Emphasize that you reached \(y = 4x - 5\) from the original equation, making it clear how you transformed the equation.

• Discuss its implications: You could explain that the slope of \(4\) indicates that for every unit increase in \(x\), \(y\) increases by \(4\), and that the \(y\)-intercept is \(-5\).

Overall, your understanding and the steps taken to arrive at the solution demonstrate a solid grasp of the material, and your presentation of this work should reflect that competence. If you're prepared to discuss and explain your solution thoroughly, you're likely to do well!