(x+10)(5x-4)=72m^2

What is the vaule of x?

1 answer

To find the value of \( x \), we need to expand and simplify the equation, then solve for \( x \).

Starting with the given equation:

\[ (x+10)(5x-4)=72m^2 \]

First, we expand the left-hand side by using the distributive property (also known as the FOIL method):

\[ x(5x) + x(-4) + 10(5x) + 10(-4) = 72m^2 \]
\[ 5x^2 - 4x + 50x - 40 = 72m^2 \]

Now, combine like terms:

\[ 5x^2 + 46x - 40 = 72m^2 \]

This equation is quadratic in terms of \( x \) and is not explicitly solvable for \( x \) without additional information about \( m \). To solve this for \( x \), we would either need a numerical value for \( m \) or we would need to express our solution in terms of \( m \).

If we needed to find the value of \( x \) in terms of \( m \), we would first need to isolate \( x \) on one side of the equation, which might involve using the quadratic formula:

\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]

Where \( a \), \( b \), and \( c \) would be the coefficients from the quadratic equation in standard form \( ax^2 + bx + c = 0 \). However, we do not have enough information to proceed further. Please provide the value of \( m \) if you need a specific numerical solution for \( x \).