To find points on the line given by the equation \( y = 2x + 3 \), we can substitute various x-values into the equation to find their corresponding y-values.
Let's compute the y-values for \( x = 0, 2, 3, 4, \) and \( 5 \):
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For \( x = 0 \): \[ y = 2(0) + 3 = 3 \] (This fills blank 1)
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For \( x = 2 \): \[ y = 2(2) + 3 = 4 + 3 = 7 \] (This fills blank 2)
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For \( x = 3 \): \[ y = 2(3) + 3 = 6 + 3 = 9 \] (This fills blank 3)
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For \( x = 4 \): \[ y = 2(4) + 3 = 8 + 3 = 11 \] (This fills blank 4)
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For \( x = 5 \): \[ y = 2(5) + 3 = 10 + 3 = 13 \] (This fills blank 5)
Now, we can summarize the answers:
- Blank 1: 3 (from \( y = 2(0) + 3 \))
- Blank 2: 7 (from \( y = 2(2) + 3 \))
- Blank 3: 9 (from \( y = 2(3) + 3 \))
- Blank 4: 11 (from \( y = 2(4) + 3 \))
- Blank 5: 13 (from \( y = 2(5) + 3 \))
So our filled-in values are:
- A: 11
- B: 13
- C: 9
- D: 9
- E: 7
- F: 13
- G: 11
- H: 7
- I: 0
In summary:
- Blank 1: 3
- Blank 2: 7
- Blank 3: 9
- Blank 4: 11
- Blank 5: 13