To determine whether Wyatt or Parker is correct regarding the congruence of the two triangles, let's examine the information provided and the relevant congruence theorems:
- Right Angle: Both triangles ABC and PQR have a right angle (∠B = 90° and ∠Q = 90°).
- Congruent Sides: It's given that
and .
Now let's apply the two congruence theorems mentioned:
-
HL Congruence Theorem: This theorem states that if a triangle has a right angle and the hypotenuse and one leg are congruent to the corresponding parts of another right triangle, then the triangles are congruent. In this case, it's not stated that
(the third side), which is necessary for applying the HL theorem. Therefore, without confirming that the lengths of the hypotenuses are equal as well, Wyatt cannot claim congruence through the HL theorem. -
SAS Congruence Theorem: This requires two sides and the included angle to be congruent. Though we have two congruent sides from the information provided, we lack information about the angle between them. Parker cannot confirm congruence through SAS without knowing an angle that is included between the two sides.
Since neither Wyatt nor Parker has enough information to definitively prove that the triangles are congruent through HL or SAS, the response that fits best is:
Both are wrong, the triangles are not congruent.
They don't have sufficient information regarding the third side or the included angle necessary for either theorem.