To determine whether Wyatt or Parker is correct in their assertion about the congruence of triangles ABC and PQR, let's analyze the information given and the criteria for triangle congruence.
-
Right Angles: Both triangles have a right angle:
- Triangle ABC: ∠B = 90°
- Triangle PQR: ∠Q = 90°
-
Sides: We know that:
- \( AB \cong QR \)
- \( AC \cong PR \)
Now, let's evaluate the two arguments:
-
Wyatt's Argument (HL Congruence Theorem): The Hypotenuse-Leg congruence theorem states that for right triangles, if the hypotenuse and one leg of one triangle are congruent to the hypotenuse and one leg of another triangle, then the triangles are congruent. Here, we have two legs (AB and AC) being compared to two sides of triangle PQR (QR and PR). We do not have the hypotenuses being mentioned in the information given, so this does not apply directly here.
-
Parker's Argument (SAS Congruence Theorem): The Side-Angle-Side theorem states that if two sides and the included angle of one triangle are congruent to the two sides and included angle of another triangle, then the triangles are congruent. However, in this case, the given information does not provide the measures of any angles besides the right angles.
Since we are comparing two right triangles with one leg and the hypotenuse (if we consider the right angles as the angle), we cannot classify this setup as SAS based solely on the provided information.
Conclusion: As neither Wyatt's use of the HL theorem nor Parker's use of the SAS theorem is applicable to the given information (especially because we're not explicitly comparing the hypotenuses), the most accurate response is:
Both are wrong, the triangles are not congruent.
So, the correct answer is: "Both are wrong, the triangles are not congruent."