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writing linear eqautions from standard form to slope-intercept form

4x-y=1

2 answers

To convert the equation from standard form \( Ax + By = C \) to slope-intercept form \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept, you can follow these steps.

Given the equation: \[ 4x - y = 1 \]

  1. Start by isolating \( y \). You can do this by moving \( 4x \) to the right side of the equation: \[ -y = -4x + 1 \]

  2. Next, multiply through by -1 to solve for \( y \): \[ y = 4x - 1 \]

Now the equation is in slope-intercept form \( y = mx + b \), where \( m = 4 \) and \( b = -1 \).

Thus, the slope-intercept form of the equation \( 4x - y = 1 \) is: \[ y = 4x - 1 \]

correct