Write y= -4x^2+8x-1 in vertex form.

y= (-4x^2+8x+2+16)-1+2+16
y= (-2x+4)^2+17 (answer)

1 answer

no, the coefficient of the x term inside the bracket should be 1

so
y= -4x^2+8x-1
= -4[x^2 - 2x ] - 1
= -4[x^2 - 2x + 1 - 1] - 1
= -4[(x-1)^2 - 1] - 1
= -4(x-1)^2 + 4 - 1
= -4(x-1)^2 + 3

so the vertex is (1,3)
Similar Questions
    1. answers icon 18 answers
  1. Is my answer correct?Write this quadratic function in the vertex form y = 4(x+5)(x-2) = 4(x² + 3x - 10) = 4(x² + 3x + 9/4 - 10
    1. answers icon 1 answer
  2. Is my answer correct?Write this quadratic function in the vertex form y = 4(x+5)(x-2) = 4(x² + 3x - 10) = 4(x² + 3x + 9/4 - 10
    1. answers icon 2 answers
    1. answers icon 1 answer
more similar questions