write y - 2 = 3/2 (x + 2) in slope-intercept form

Answer 1

To write the equation y - 2 = 3/2 (x + 2) in slope-intercept form (y = mx + b), we need to isolate y on one side of the equation.

First, distribute the 3/2 to both terms in the parentheses:
y - 2 = 3/2 * x + 3/2 * 2
y - 2 = 3/2x + 3

Next, move the constant term (-2) to the other side of the equation by adding 2 to both sides:
y = 3/2x + 3 + 2
y = 3/2x + 5

Therefore, the equation y - 2 = 3/2 (x + 2) in slope-intercept form is y = 3/2x + 5.