Write y−2=3/2(x+2) in slope-intercept form.(1 point)

Question

y=3/2x+3/2

y=3/2x+5

y=3/2x+6

y=3/2+5x

Answer 1

To write the equation y - 2 = 3/2(x + 2) in slope-intercept form, we would need to solve for y.

First, distribute the 3/2 to both terms inside the parentheses:

y - 2 = 3/2x + 3

Next, isolate the y-term by adding 2 to both sides of the equation:

y = 3/2x + 3 + 2

Simplifying, we get:

y = 3/2x + 5

Therefore, the equation y - 2 = 3/2(x + 2) in slope-intercept form is y = 3/2x + 5.

Answer 2

Identify the slope and the y-intercept of the equation 4x−3y=12.(1 point)

The slope is 43, and the y-intercept is (0, −4).

The slope is 4, and the y-intercept is (0, 12).

The slope is −43, and the y-intercept is (0, 4).

The slope is 43, and the y-intercept is (0, 4).

Answer 3

To identify the slope and the y-intercept of the equation 4x - 3y = 12, we need to rearrange the equation into slope-intercept form, which is y = mx + b, where m represents the slope and b represents the y-intercept.

To do so, we isolate the y-term by subtracting 4x from both sides of the equation:

-3y = -4x + 12

Next, divide both sides of the equation by -3 to solve for y:

y = (4/3)x - 4

From this equation, we can determine that the slope is 4/3 and the y-intercept is (0, -4).

Therefore, the correct answer is: The slope is 4/3, and the y-intercept is (0, -4).