write y = 1/6x + 4 in standard form using intergers

Answer 1

To write the equation y = (1/6)x + 4 in standard form with integers, we need to eliminate any fractions.

First, we multiply every term in the equation by 6 to get rid of the fraction:
6y = 6 * (1/6)x + 6 * 4

This simplifies to:
6y = x + 24

Next, we want to rearrange the equation so that all terms are on one side and the coefficient of x is positive (for standard form). To achieve this, we subtract x from both sides:
-x + 6y = x - x + 24

This simplifies to:
-x + 6y = 24

Since the standard form equation should only have integer coefficients, we can multiply through by -1 to make the coefficient of x positive:
x - 6y = -24

Thus, the equation y = (1/6)x + 4 in standard form with integers is x - 6y = -24.