(2-3i)+(6+5i)
=2-3i+6+5i
=2+6 -3i+5i
=8+2i
You can do the same procedure for the second part, but change √-9 into 3i before.
write the sum or difference in the standard form a+bi
(2-3i)+(6+5i)
(squareroot5-3i)+(-2+squareroot-9)
1 answer