Write the standard equation for the parabola with the given characteristics.

Question

vertex:(0,0)
directrix:y= -1.

Answer 1

The equation x^2 = 4 py is a parabola with vertex at (0,0) and a directrix below it at y = -p. You want p to be 1.

Therefore 4p = 1 and p = 1/4

y = x^2 /4 is the equation