since the slope of y=-2x+5 is -2, you want a line with slope = 1/2
so start with the point-slope form:
y+5 = 1/2 (x+4)
now just rearrange as desired
write the slope intercept form of the equation of the line described
through (-4,-5) perpendicular to y=-2x+5
steps please but not too long though
3 answers
perpendicular lines have slopes which are negative-reciprocals
-2 ---> 1/2
using point-slope ... y + 5 = 1/2 (x + 4)
solving for y ... y = 1/2 x - 3
-2 ---> 1/2
using point-slope ... y + 5 = 1/2 (x + 4)
solving for y ... y = 1/2 x - 3
Perpendicular lines have slopes which are negative reciprocals.
In this case:
y = - 2 x + 5
Slope of this line is - 2
Slope of perpendicular line is negative reciprocals :
m = – 1 / ( - 2 ) = 1 / 2
Slope-Intercept form of a straight line :
y = m x + b
y = 1 / 2 x + b
Put x = - 4 , y = - 5 in this equation
- 5 = ( 1 / 2 ) • ( - 4 ) + b
- 5 = - 2 + b
Add 2 to both sides
- 3 = b
b = - 3
So equation of your perpendicular line:
y = 1 / 2 x + b
y = 1 / 2 x - 3
In this case:
y = - 2 x + 5
Slope of this line is - 2
Slope of perpendicular line is negative reciprocals :
m = – 1 / ( - 2 ) = 1 / 2
Slope-Intercept form of a straight line :
y = m x + b
y = 1 / 2 x + b
Put x = - 4 , y = - 5 in this equation
- 5 = ( 1 / 2 ) • ( - 4 ) + b
- 5 = - 2 + b
Add 2 to both sides
- 3 = b
b = - 3
So equation of your perpendicular line:
y = 1 / 2 x + b
y = 1 / 2 x - 3