Write the series using sigma notation: 100+90+81

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To express the series \(100 + 90 + 81\) using sigma notation, we can identify a pattern in the terms.

  1. Identifying the pattern:
    • The first term is \(100\).
    • The second term is \(90\) (which is \(100 - 10\)).
    • The third term is \(81\) (which is \(90 - 9\) or \(100 - 19\)).

The pattern can be seen as a decreasing sequence: the first term is \(10^2\), the second term is \(9^2\), and the third term is \(8^2\). We can generalize this to include the squares of decreasing integers starting from \(10\).

  1. Writing in sigma notation: The series can be expressed in the following way:

\[ \sum_{n=8}^{10} n^2 \]

This notation indicates that we are summing the squares of the integers from \(8\) to \(10\), which corresponds to the terms \(8^2 + 9^2 + 10^2 = 64 + 81 + 100\), but we need a correction to map correctly to the series we are actually summing.

Instead, noting the terms clearly, the sigma notation for the specific series you provided should reflect the terms themselves:

\[ \sum_{k=0}^{2} (10-k)^2 \]

Here, when \(k=0\), it yields \(10^2 = 100\), when \(k=1\), it yields \(9^2 = 90\), and when \(k=2\), it yields \(8^2 = 81\).

Thus, an accurate sigma notation would be:

\[ \sum_{k=0}^{2} (10-k)^2 \]

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