Graph of Y = x^2.
(X , Y)
(-2 , 4)
(-1 , 1)
V(0 , 0)
(1 , 1)
(2 , 4).
Add -4 to each value of X. Add 3/2(1.5)
to each Y value:
(X , Y)
(-6 , 5.5)
(-5 , 2.5)
V(-4 , 1.5)
(-3 , 2.5)
(-2 , 5.5)
Graph the two parabolas on the same graph for better comparison.
V(-4 , 1.5), P(-3 , 2.5).
Y = a(x - h)^2 + k.
2.5 = a(-2 + 4)^2 + 1.5,
2.5 = a + 1.5,
-a = 1.5 - 2.5,
-a = -1,
a = 1.
Eq2: Y = (X + 4)^2 + 1.5.
Write the relation for a parabola that satisfies each condition:
The graph of y=x^2 is stretched vertically by a factor of 3/2, then translated left 4 units.
1 answer