Write the reactions that occur for the benzoic acid/sodium benzoate buffer when you react it with HNO3 and KOH. How would I go about writing it? Thanks.

Answer 1

Let's call benzoic acid HBz and the benzoate ion then is Bz^-

With HNO3, the added acid (HNO3) reacts with the base, Bz^-.
Bz^- + H^+ ==> HBz

With KOH, the added base (KOH) reacts with the acid, HBz.
HBz + OH^- ==> Bz^- + H2O

Answer 2

Thank you so much!!!!