Let's call benzoic acid HBz and the benzoate ion then is Bz^-
With HNO3, the added acid (HNO3) reacts with the base, Bz^-.
Bz^- + H^+ ==> HBz
With KOH, the added base (KOH) reacts with the acid, HBz.
HBz + OH^- ==> Bz^- + H2O
Write the reactions that occur for the benzoic acid/sodium benzoate buffer when you react it with HNO3 and KOH. How would I go about writing it? Thanks.
2 answers
Thank you so much!!!!