Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
Write the quadratic equation in standard form: x, squared, minus, 1, equals, minus, 7, x x 2 −1= −7xQuestion
Write the quadratic equation in standard form:
4, x, squared, plus, 8, equals, minus, 5, x
4x
2
+8=
−5x
4, x, squared, plus, 8, equals, minus, 5, x
4x
2
+8=
−5x
Answers
Answer
Write the quadratic equation in standard form:
8, x, squared, minus, 8, x, minus, 15, equals, 5, x, squared
8x
2
−8x−15=
5x
2
8, x, squared, minus, 8, x, minus, 15, equals, 5, x, squared
8x
2
−8x−15=
5x
2
Answer
Factor the expression completely.
20, x, to the power 4 , plus, 45, x, to the power 5
20x
4
+45x
5
20, x, to the power 4 , plus, 45, x, to the power 5
20x
4
+45x
5
Answer
Factor the expression completely.
36, x, to the power 4 , minus, 28, x, squared
36x
4
−28x
2
36, x, to the power 4 , minus, 28, x, squared
36x
4
−28x
2
Answer
Solve the equation for all values of xx.
x, squared, minus, 49, equals, 0
x
2
−49=
0
x, squared, minus, 49, equals, 0
x
2
−49=
0
Answer
Solve the equation for all values of xx.
x, squared, minus, 121, equals, 0
x
2
−121=
0
x, squared, minus, 121, equals, 0
x
2
−121=
0
Answered by
GPT-4o mini
To write the given equation \( 4x^2 + 8 = -5x \) in standard form, we need to rearrange the equation so that one side equals zero.
Starting with the original equation:
\[
4x^2 + 8 = -5x
\]
We can add \( 5x \) to both sides to move everything to one side of the equation:
\[
4x^2 + 5x + 8 = 0
\]
Now, the equation is in standard form, which is:
\[
4x^2 + 5x + 8 = 0
\]
Starting with the original equation:
\[
4x^2 + 8 = -5x
\]
We can add \( 5x \) to both sides to move everything to one side of the equation:
\[
4x^2 + 5x + 8 = 0
\]
Now, the equation is in standard form, which is:
\[
4x^2 + 5x + 8 = 0
\]
Answered by
GPT-4o mini
To write the equation \( 8x^2 - 8x - 15 = 5x^2 \) in standard form, we need to rearrange it so that all terms are on one side of the equation, leaving the other side equal to zero.
Starting with:
\[
8x^2 - 8x - 15 = 5x^2
\]
We can subtract \( 5x^2 \) from both sides:
\[
8x^2 - 5x^2 - 8x - 15 = 0
\]
Now combine like terms:
\[
(8x^2 - 5x^2) - 8x - 15 = 0
\]
This simplifies to:
\[
3x^2 - 8x - 15 = 0
\]
So the quadratic equation in standard form is:
\[
3x^2 - 8x - 15 = 0
\]
Starting with:
\[
8x^2 - 8x - 15 = 5x^2
\]
We can subtract \( 5x^2 \) from both sides:
\[
8x^2 - 5x^2 - 8x - 15 = 0
\]
Now combine like terms:
\[
(8x^2 - 5x^2) - 8x - 15 = 0
\]
This simplifies to:
\[
3x^2 - 8x - 15 = 0
\]
So the quadratic equation in standard form is:
\[
3x^2 - 8x - 15 = 0
\]
Answered by
GPT-4o mini
To factor the expression \( 20x^4 + 45x^5 \) completely, we can start by identifying the greatest common factor (GCF) of the two terms.
1. **Identify the GCF**:
- The coefficients are 20 and 45. The GCF of 20 and 45 is 5.
- For the variable part, the lowest power of \( x \) in both terms is \( x^4 \).
So, the GCF of the entire expression is \( 5x^4 \).
2. **Factor out the GCF**:
Now, we can factor out \( 5x^4 \) from the original expression:
\[
20x^4 + 45x^5 = 5x^4(4 + 9x)
\]
3. **Check for further factorization**:
The remaining expression \( 4 + 9x \) cannot be factored further in terms of integers or simpler polynomials.
Thus, the completely factored form of the expression is:
\[
\boxed{5x^4(4 + 9x)}
\]
1. **Identify the GCF**:
- The coefficients are 20 and 45. The GCF of 20 and 45 is 5.
- For the variable part, the lowest power of \( x \) in both terms is \( x^4 \).
So, the GCF of the entire expression is \( 5x^4 \).
2. **Factor out the GCF**:
Now, we can factor out \( 5x^4 \) from the original expression:
\[
20x^4 + 45x^5 = 5x^4(4 + 9x)
\]
3. **Check for further factorization**:
The remaining expression \( 4 + 9x \) cannot be factored further in terms of integers or simpler polynomials.
Thus, the completely factored form of the expression is:
\[
\boxed{5x^4(4 + 9x)}
\]
Answered by
GPT-4o mini
To factor the expression \( 36x^4 - 28x^2 \) completely, we will follow these steps:
1. **Identify the Greatest Common Factor (GCF)**:
- The coefficients are 36 and 28. The GCF of 36 and 28 is 4.
- For the variable part, the lowest power of \( x \) in both terms is \( x^2 \).
So, the overall GCF of \( 36x^4 - 28x^2 \) is \( 4x^2 \).
2. **Factor out the GCF**:
Now, we can factor out \( 4x^2 \):
\[
36x^4 - 28x^2 = 4x^2(9x^2 - 7)
\]
3. **Check for further factorization**:
Next, we look at the expression inside the parentheses, \( 9x^2 - 7 \). This is a difference of squares format but is not factorable into integer coefficients.
Thus, the completely factored form of the expression is:
\[
\boxed{4x^2(9x^2 - 7)}
\]
1. **Identify the Greatest Common Factor (GCF)**:
- The coefficients are 36 and 28. The GCF of 36 and 28 is 4.
- For the variable part, the lowest power of \( x \) in both terms is \( x^2 \).
So, the overall GCF of \( 36x^4 - 28x^2 \) is \( 4x^2 \).
2. **Factor out the GCF**:
Now, we can factor out \( 4x^2 \):
\[
36x^4 - 28x^2 = 4x^2(9x^2 - 7)
\]
3. **Check for further factorization**:
Next, we look at the expression inside the parentheses, \( 9x^2 - 7 \). This is a difference of squares format but is not factorable into integer coefficients.
Thus, the completely factored form of the expression is:
\[
\boxed{4x^2(9x^2 - 7)}
\]
Answered by
GPT-4o mini
To solve the equation \( x^2 - 49 = 0 \), we can factor the left-hand side. Notice that this is a difference of squares:
\[
x^2 - 49 = (x - 7)(x + 7)
\]
Setting the factored equation equal to zero gives us:
\[
(x - 7)(x + 7) = 0
\]
Now, we can set each factor to zero:
1. \( x - 7 = 0 \)
\[
x = 7
\]
2. \( x + 7 = 0 \)
\[
x = -7
\]
Thus, the solutions to the equation \( x^2 - 49 = 0 \) are:
\[
\boxed{7} \quad \text{and} \quad \boxed{-7}
\]
\[
x^2 - 49 = (x - 7)(x + 7)
\]
Setting the factored equation equal to zero gives us:
\[
(x - 7)(x + 7) = 0
\]
Now, we can set each factor to zero:
1. \( x - 7 = 0 \)
\[
x = 7
\]
2. \( x + 7 = 0 \)
\[
x = -7
\]
Thus, the solutions to the equation \( x^2 - 49 = 0 \) are:
\[
\boxed{7} \quad \text{and} \quad \boxed{-7}
\]
Answered by
GPT-4o mini
To solve the equation \( x^2 - 121 = 0 \), we can recognize that this is also a difference of squares:
\[
x^2 - 121 = (x - 11)(x + 11)
\]
Now, we can set each factor equal to zero:
1. \( x - 11 = 0 \)
\[
x = 11
\]
2. \( x + 11 = 0 \)
\[
x = -11
\]
Thus, the solutions to the equation \( x^2 - 121 = 0 \) are:
\[
\boxed{11} \quad \text{and} \quad \boxed{-11}
\]
\[
x^2 - 121 = (x - 11)(x + 11)
\]
Now, we can set each factor equal to zero:
1. \( x - 11 = 0 \)
\[
x = 11
\]
2. \( x + 11 = 0 \)
\[
x = -11
\]
Thus, the solutions to the equation \( x^2 - 121 = 0 \) are:
\[
\boxed{11} \quad \text{and} \quad \boxed{-11}
\]
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.