r = 12 sinθ
r^2 = 12r sinθ
x^2+y^2 = 12x
x^2 - 12x + y^2 = 0
(x-6)^2 + y^2 = 36
This one is just the reverse process:
(x+7)^2 + y^2 = 49
x^2 + 14x + y^2 = 0
x^2 + y^2 = -14x
r^2 = -14r cosθ
r = -14 cosθ
Write the polar equation in rectangular form. r = 12 sin theta
Write the rectangular equation (x + 7)^2 + y^2 = 49 in polar form
3 answers
thank you!
I mixed up x and y in the 1st one!
x^2+y^2 = 12y
x^2 - 12y + y^2 = 0
x^2 + (y-6)^2 = 36
Also, the 2nd one could just as well have been written r = 14cosθ. It would just draw the circle from the left, rather than from the right.
x^2+y^2 = 12y
x^2 - 12y + y^2 = 0
x^2 + (y-6)^2 = 36
Also, the 2nd one could just as well have been written r = 14cosθ. It would just draw the circle from the left, rather than from the right.