Write the overall net-ionic reaction that occurs when iron (ii) hydroxide (Fe(OH)2, Ksp = 7.9 x 10^-15) is dissolved in a 0.500 M sodium cyanide solution forming a complex ion. (Fe(CN)6^4-, Kf = 7.7 x 10^36)

Determine the value of the equilibrium constant for the overall net-ionic reaction.

Which chemical is the ligand in the complex ion?

3 answers

Fe(OH)2 ==> Fe^2+ + 2OH^- Ksp = ?
Fe^2+ + 6CN^- ==> [Fe(CN6]^4 Kf = ?
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Fe(OH)2+ 6CN^- => Fe^2+ +2OH^- +[Fe(CN)6]^4-

CN^- is the ligand
Keq for the rxn as shown is Kf*Ksp = ?
do I have to find Ksp using the .5M?
No. K is K. It changes ONLY with temperature. Ksp is given Kf is given. If you wonder how I know Keq is Kf*Ksp, here is what you do.
Write the Ksp expression and multiply that by the Kf