Write the net ionic equation for the following molecular equation.

Question

3FeI2 (aq) + 2(NH4)3PO4 (aq) --> Fe3(PO4)2 (s) + 6NH4I (aq)
(Use the lowest possible coefficients. Use the pull-down boxes to specify states such as (aq) or (s). If a box is not needed, leave it blank.)

Answer 1

I'm unclear about the boxes and I don't see any pull down boxes.
3FeI2 (aq) + 2(NH4)3PO4 (aq) --> Fe3(PO4)2 (s) + 6NH4I (aq)
3Fe^2+(aq) + 6I^-(aq) + 6NH4^+(aq) + 2PO4^3- (aq) ==> Fe3(PO4)2(s) + 6NH4^+(aq) + 6I^-(aq)
Now cancel those ions that appear on both sides to obtain the final which is the net ionic equation.
3Fe^2+(aq) + 2PO4^3-(aq) ==> Fe3(PO4)2 (s)