Write the linear equation 3y = 6x − 18 in slope-intercept form

1 answer

To write the equation \(3y = 6x - 18\) in slope-intercept form, we need to solve for \(y\), which is in the form \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept.

Starting with the equation:

\[ 3y = 6x - 18 \]

We divide every term by 3 to isolate \(y\):

\[ y = \frac{6x}{3} - \frac{18}{3} \]

This simplifies to:

\[ y = 2x - 6 \]

Now the equation is in slope-intercept form. The slope \(m\) is 2, and the y-intercept \(b\) is -6.

The final slope-intercept form of the equation is:

\[ y = 2x - 6 \]