Write the linear equation 3y=6x−18 in slope-intercept form.(

Answer 1

To write the equation in slope-intercept form, we need to solve for y.

First, let's add 18 to both sides of the equation to isolate the constant term on the right side:
3y + 18 = 6x

Next, we divide both sides of the equation by 3 to isolate y:
(3y + 18)/3 = 6x/3
y + 6 = 2x

Finally, subtract 6 from both sides of the equation to isolate y on the left side:
y + 6 - 6 = 2x - 6
y = 2x - 6

Therefore, the linear equation 3y = 6x - 18 in slope-intercept form is y = 2x - 6.