130
∑ 3^(3-k)
k=1
Write the geometric series 9+3+1..... to 130 term in sigma notation
2 answers
The general term is 3^(3 - n)
so ∑ (3)^(3-n) , were n = 1 to 130
so ∑ (3)^(3-n) , were n = 1 to 130