To represent the sequence in the table you've provided, we can analyze the values in the second row:
- For \( x = 1 \), \( f(1) = 6 \)
- For \( x = 2 \), \( f(2) = 24 \)
- For \( x = 3 \), \( f(3) = 96 \)
- For \( x = 4 \), \( f(4) = 384 \)
Let's examine the pattern in the function values:
- Find the ratio of consecutive values:
- \( \frac{f(2)}{f(1)} = \frac{24}{6} = 4 \)
- \( \frac{f(3)}{f(2)} = \frac{96}{24} = 4 \)
- \( \frac{f(4)}{f(3)} = \frac{384}{96} = 4 \)
The function values are multiplied by 4 as \( x \) increases by 1, suggesting an exponential relationship.
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Check if the function fits a standard form: Given the common ratio, we can hypothesize that \( f(x) = k \cdot 4^{x-1} \) for some constant \( k \).
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Determine \( k \):
- We can find \( k \) using the value of \( f(1) \):
- \( f(1) = k \cdot 4^{1-1} = k \cdot 1 = k \)
- Since \( f(1) = 6 \), we find that \( k = 6 \).
- We can find \( k \) using the value of \( f(1) \):
Thus, we have the function:
\[ f(x) = 6 \cdot 4^{x-1} \]
This matches the values given in the table. Therefore, the function that represents the sequence in the table is:
\[ \boxed{6 \cdot 4^{x-1}} \]