write the following infinite expansion as a fraction. you do not need to simplify.

0.329329329...

1 answer

To express the repeating decimal \( 0.329329329... \) as a fraction, we can follow these steps:

Let \( x = 0.329329329... \).

Notice that the decimal has a repeating block of three digits (329). To eliminate the repeating part, multiply \( x \) by \( 1000 \) (since the block has three digits):

\[ 1000x = 329.329329329... \]

Now, we have two equations:

  1. \( x = 0.329329329... \)
  2. \( 1000x = 329.329329329... \)

Next, we subtract the first equation from the second:

\[ 1000x - x = 329.329329329... - 0.329329329... \]

This simplifies to:

\[ 999x = 329 \]

Now, to express \( x \) as a fraction, we divide both sides by 999:

\[ x = \frac{329}{999} \]

Thus, the infinite expansion \( 0.329329329... \) can be written as the fraction \( \frac{329}{999} \).