Write the first three terms of the following geometric sequence: tn = 3(1/2)n-1.

Answer 1

n Tn
1 3(1/2)^0 = 3
2 3(1/2)^1 = 3(1/2) = 3/2
3 3(1/2)^2 = 3(1/4) = 3/4

what's the problem? They gave you the formula; just plug in values for n.