write the expression (4x-2)*6(2x+7) in the standerd form of a quadratic equation, ax^(2)+bx+c what are the values of the coefficient of each term and the constant term

Answer 1

To convert the expression (4x-2)*6(2x+7) to the standard form of a quadratic equation, we need to simplify and expand it.

First, distribute the 6 to each term inside the parentheses:

(4x-2)*6(2x+7) = 6(4x*2x + 4x*7 - 2*2x - 2*7)
= 6(8x^2 + 28x - 4x - 14)

Simplifying further:

= 6(8x^2 + 24x - 14)

Now distribute the 6 to each term inside the parentheses:

= 48x^2 + 144x - 84

The equation is now in the standard form:

ax^2 + bx + c = 48x^2 + 144x - 84

The coefficients are:
a = 48
b = 144
c = -84