I believe you need to reverse your cell.
1M Cd/Cd^2+ is 0.403 as an oxidation.
1M In/In^3+ is 0.342 as an oxidation.
Therefore, Cd will be the anode and In the cathode.
3Cd + 2In^3+ ==> 3Cd^2+ + 2In
Write the equations describing the electrode reactions and the net cell reaction for this electrochemical cell containing indium and cadmium:
This is what I have so far:
anode: In(s) --> In^3+ + 3e-
cathode: Cd^2+ + 2e- --> Cd (s)
Need help writing the balanced net reaction!
2 answers
DrBob222's answer is wrong.
You mean to put Cd/Cd^2+ is -0.403, not 0.403.
Answer is:
3Cd^2+(aq) + 2In(s) --> 3Cd(s) + 2In^3+(aq)
this is right because the short hand notation is:
In(s)|In^3+ (aq)||Cd^2+ (aq)|Cd(s)
And the Anode is always on the left.
~Information valid. College student experience and in the class now.
You mean to put Cd/Cd^2+ is -0.403, not 0.403.
Answer is:
3Cd^2+(aq) + 2In(s) --> 3Cd(s) + 2In^3+(aq)
this is right because the short hand notation is:
In(s)|In^3+ (aq)||Cd^2+ (aq)|Cd(s)
And the Anode is always on the left.
~Information valid. College student experience and in the class now.
3 answers