Write the equation x^2+y^2-2x-4y-11=0 in standard form.

Answer 1

x^2-2x+1+y^2 -4y+4-11-1+4=0
(x-1)^2 + (y-2)^2=8

Answer 2

Wait! It just appears (x-1)^2 + (y-2)^2=16 and (x-1)^2 + (y-2)^2=4 so it would be this one?
I think its this one (x-1)^2 + (y-2)^2=16
what about you?