First, let's find the slope of the line using the formula:
m = (y2 - y1)/(x2 - x1)
m = (6 - (-7))/(-2 - 3)
m = (6 + 7)/(-5)
m = 13/-5
m = -13/5
Now that we have the slope, we can use the point-slope form of the equation to find the linear function:
y - y1 = m(x - x1)
Using the point (3, -7):
y - (-7) = -13/5(x - 3)
y + 7 = -13/5(x - 3)
y + 7 = -13/5x + 39/5
y = -13/5x + 39/5 - 7
y = -13/5x + 39/5 - 35/5
y = -13/5x + 4/5
Therefore, the equation of the linear function passing through the points (3, -7) and (-2, 6) is y = -13/5x + 4/5.
Write the equation of the linear function that passes through the points ( 3,−7) and ( −2, 6).
1 answer