First, we need to find the slope (m) of the line using the two given points.
m = (y2 - y1) / (x2 - x1)
m = (13 - (-2)) / (-3 - 2)
m = 15 / -5
m = -3
Now that we have the slope, we can use one of the points to find the y-intercept (b) of the line.
Using point (2,-2):
-2 = -3(2) + b
-2 = -6 + b
b = 4
So the equation of the linear function passing through the points (2,-2) and (-3,13) is:
y = -3x + 4
Write the equation of the linear function that passes through the points (2,-2) and (-3,13)
y= ___ x + ___
1 answer
1 answer