First, we need to find the slope (m) of the line using the formula:
m = (y₂ - y₁) / (x₂ - x₁)
m = (3 - 2) / (0 - 2)
m = 1 / -2
m = -1/2
Now that we have the slope, we can use one of the points to find the y-intercept (b) using the formula y = mx + b. Let's use the point (2, 2):
2 = (-1/2)(2) + b
2 = -1 + b
b = 3
Therefore, the equation of the linear function passing through the points (2, 2) and (0, 3) is:
y = -1/2x + 3
Write the equation of the linear function that passes through the points (2,2) and (0,3)
y =___x +___
1 answer
1 answer