The slope-intercept form of the equation of a line is y = mx + b, where m is the slope and b is the y-intercept.
We are given the slope m = -4 and a point on the line (-6, 5). We can use the point-slope form of the equation of a line to find the equation in slope-intercept form.
y - y1 = m(x - x1) (point-slope form)
Substituting the values, we get:
y - 5 = -4(x - (-6))
y - 5 = -4(x + 6)
y - 5 = -4x - 24
y = -4x - 19
Therefore, the equation of the line in slope-intercept form is y = -4x - 19.
Write the equation of the line, with the given properties, in slope-intercept form.
slope = -4, through (-6, 5)
3 answers
y = mx + b
5 = (-6)(-4) + b
5 = 24 + b
-19 = b
Our y-intercept is 19. Now, our equation is:
y = 6-x + (-19)
Not sure if my answer is correct. can someone check my solution?
5 = (-6)(-4) + b
5 = 24 + b
-19 = b
Our y-intercept is 19. Now, our equation is:
y = 6-x + (-19)
Not sure if my answer is correct. can someone check my solution?
Actually the answer by the bot is correct